spring mvc 怎么获取json

发布网友发布时间：2022-05-07 18:48

共2个回答

热心网友时间：2022-05-15 07:11

首先准备以下 jar包:
commons-logging-1.1.3.jar
jackson-core-asl-1.9.2.jar
jackson-mapper-asl-1.9.2.jar
spring-aop-4.0.6.RELEASE.jar
spring-beans-4.0.6.RELEASE.jar
spring-context-4.0.6.RELEASE.jar
spring-core-4.0.6.RELEASE.jar
spring-expression-4.0.6.RELEASE.jar
spring-web-4.0.6.RELEASE.jar
spring-webmvc-4.0.6.RELEASE.jar
其中commons-logging-1.1.3.jar,jackson-core-asl-1.9.2.jar,jackson-mapper-asl-1.9.2.jar均可在struts2的工具包中取得

导入以上包后,去web.xml中进行配置,配置文件如下:

<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
id="WebApp_ID"
version="3.1"> <display-name>web</display-name>
 <servlet> <servlet-name>springMVC</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/*-servlet.xml</param-value> </init-param>
-->  <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>springMVC</servlet-name>  <url-pattern>*.do</url-pattern> </servlet-mapping>
<welcome-file-list> <welcome-file>index.html</welcome-file> <welcome-file>index.htm</welcome-file> <welcome-file>index.jsp</welcome-file> <welcome-file>default.html</welcome-file> <welcome-file>default.htm</welcome-file> <welcome-file>default.jsp</welcome-file> </welcome-file-list></web-app>

接下来我们再看springMVC-servlet.xml,如下:

<?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">  <context:component-scan base-package="org.xt.controller"/>  <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">  <property name="prefix" value="/WEB-INF/page"/>  <property name="suffix" value=".jsp"/> </bean>  <bean id="jsonMapping" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> <property name="messageConverters"> <list> <ref bean="jsonMapping"/> </list> </property> </bean></beans>

接下来我们再看vo对象即值对象User.java,如下:

package org.xt.pojo;import java.io.Serializable;

@SuppressWarnings("serial")public class User implements Serializable { private long userId; private String userName; private String userPassword; public long getUserId() { return this.userId;
} public void setUserId(long userId) { this.userId = userId;
} public String getUserName() { return this.userName;
} public void setUserName(String userName) { this.userName = userName;
} public String getUserPassword() { return this.userPassword;
} public void setUserPassword(String userPassword) { this.userPassword = userPassword;
}
}

好接下来便轮到了Controller的类TestJSONController.java,如下:

package org.xt.controller;import org.springframework.stereotype.Controller;import org.springframework.web.bind.annotation.RequestBody;import org.springframework.web.bind.annotation.RequestMapping;import org.springframework.web.bind.annotation.RequestMethod;import org.springframework.web.bind.annotation.ResponseBody;import org.xt.pojo.User;

@Controller
@RequestMapping("/test")public class TestJSONController { /*
*看value属性,是以do结尾的,这正是web.xml配置url-pattern的值为*.do的原因,
*这样所有的请求链接都必须以.do结尾,这样做的好处在于可以将请求链接同其他链接区分开来.
*笔者建议如此做(当然了,你也可以将.do换成.html,.htm或者其他) */
@RequestMapping(value = "/testJSON.do",method={RequestMethod.POST})
@ResponseBody public User testJSON(@RequestBody User user) {
System.out.println(user.getUserName() + " " + user.getUserPassword()); return user;
}
}

在以上类中出现的@ResponseBody和@RequestBody是关键,前者用于将JSON数据返回客户端,后者用于接受客户端的JSON数据

接下来我们来看看客户端的代码,客户端的代码由jquery完成

<%@ page language="java" contentType="text/html;charset=UTF-8" pageEncoding="UTF-8"%><!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html><head><meta http-equiv="Content-Type" content="text/html;charset=UTF-8"><title>TestJSONForSpringMVC</title></head><body>
用户名: <input id="userName" type="text" style="width:150px" /> <br />
<br />
密    码: <input id="userPassword" type="password" style="width:150px" /> <br /> <br /> <input id="login" type="button" value="登录" />  <script type="text/javascript" src="jquery.js"></script> <script type="text/javascript">
$("#login").click(function() {
$.ajax({
url : "test/testJSON.do",
type : "POST",
dataType : "json",
contentType : "application/json;charset=UTF-8",
data : JSON.stringify({
userId : "1",
userName : $("#userName").val(),
userPassword : $("#userPassword").val()
}),
success : function(result) {
alert(JSON.stringify(result));
},
error:function(result){
alert("Sorry,you are make a error!");
}
});
});
</script></body></html>

以上jsp文件中出现了一个JSON.stringify()函数,此函数由jquery提供,作用在于将JSON数据转换为字符串,之所以要这么做,原因在于服务端的@RequestBody只能识别字符串,而不能识别JSON对象

热心网友时间：2022-05-15 08:29

@ResponseBody 是一种，试图解析器配置协商试图解析器。
如果自己已经生成json字符串，自己实现视图与视图解析器（继承spring实现好的解析器）。