...A(3,-2),x轴上确定一点P,使△AOP为等腰三角形,则符合条件的P点的坐...
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发布时间:2024-10-14 06:31
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时间:2024-11-05 07:20
解:如图,OA=22+32=13;
①若OA=AP,则点P1(6,0);
②若OA=OP,则点P2(13,0),P3(-13,0);
③若OP=AP,则P4(136,0);
∴符合条件的P点的坐标为:(6,0),(13,0),(-13,0),(136,0).
故答案为:(6,0),(13,0),(-已赞过已踩过你对这个回答的评价是?评论收起 ._1uevpeq{zoom:1;background-color:#fff;border:0;margin-bottom:10px;padding:30px 0 20px 42px;position:relative}._1uevpeq.ec-1841{padding:20px 0}._1uevpeq.ec-2246{padding:20px 0 10px}.ec-1841 .y7we4hu{font-size:16px;margin-bottom:-5px}.y7we4hu{color:#7a8f9a;height:25px;line-height:25px;overflow:hidden;position:relative}.y7we4hu h2{margin:0;padding:0}.y7we4hu:after{clear:both;content:" ";display:block;height:0;visibility:hidden}a.tycfu7u{color:#666;float:right;font-size:12px;margin-left:8px;text-decoration:none}.hhhv6ex{color:#666;font-size:13px;line-height:normal;line-height:20px;margin-top:10px}.vnsdjzp{margin-top:15px;position:relative}.vnsdjzp h3{font-weight:400;padding:0}.vnsdjzp a{text-decoration:none}.vnsdjzp em{color:#d81419;font-style:normal}.ec-2246 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