用因式分解法,解(x一3)的平方=2x一6,求过程
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发布时间:2024-10-17 22:43
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热心网友
时间:2024-11-23 23:04
( x - 3 )" = 2x - 6
( x - 3 )" = 2( x - 3 )
( x - 3 )" - 2( x - 3 ) = 0
( x - 3 )( x - 3 - 2 ) = 0
( x - 3 )( x - 5 ) = 0
解方程得
x1 = 3,
x2 = 5
热心网友
时间:2024-11-23 23:05
(x-3)²=2x-6
(x-3)²=2(x-3)
(x-3)²-2(x-3)=0
(x-3)(x-3-2)=0
(x-3)(x-5)=0
x=3,x=5