请问matlab如何分解这个多项式

发布网友发布时间：2022-05-07 01:40

共1个回答

热心网友时间：2023-10-11 07:31

syms a b c d e x y;
y = a*x^4/(b-c*x^2-d*x^3)+e
simple(y)

simplify:
(-a*x^4-e*b+e*c*x^2+e*d*x^3)/(-b+c*x^2+d*x^3)

radsimp:
(-a*x^4-e*b+e*c*x^2+e*d*x^3)/(-b+c*x^2+d*x^3)

combine(trig):
(-a*x^4-e*b+e*c*x^2+e*d*x^3)/(-b+c*x^2+d*x^3)

factor:
(-a*x^4-e*b+e*c*x^2+e*d*x^3)/(-b+c*x^2+d*x^3)

expand:
a*x^4/(b-c*x^2-d*x^3)+e

combine:
a*x^4/(b-c*x^2-d*x^3)+e

convert(exp):
a*x^4/(b-c*x^2-d*x^3)+e

convert(sincos):
a*x^4/(b-c*x^2-d*x^3)+e

convert(tan):
a*x^4/(b-c*x^2-d*x^3)+e

collect(x):
a*x^4/(b-c*x^2-d*x^3)+e

mwcos2sin:
a*x^4/(b-c*x^2-d*x^3)+e

ans =
a*x^4/(b-c*x^2-d*x^3)+e

追问用手算很简单

a * x^4 / (b - c * x^2 - d * x^3) + e = 0

a * x^4+e * (b - c * x^2 - d * x^3) =0
我想要的结果是 a * x^4 + d * e * x^3 + c * e * x^2 + 0 * x + b * e = 0
您给出的代码并没有我想要的答案啊，请问如何解决这个问题啊