化简求值sin(-20/3π)cos(43/6π)+sin(35/6π)cos-(17/3π)
发布网友
发布时间:2024-09-30 21:36
我来回答
共1个回答
热心网友
时间:2024-10-28 23:51
sin(-20/3π)cos(43/6π)+sin(35/6π)cos-(17/3π)
=sin(-2/3π)cos(7/6π)+sin(-1/6π)cos(1/3π)
=sin(1/3π)cos(1/6π)-sin(1/6π)cos(1/3π)
=sin(1/3π-1/6π)=-1/2
[2sin50°+cos10°(1+根号(3)tan10°)]/根号(1+cos10°)
=[2sin50°+cos10°+根号(3)sin10°)]/(根号(2)cos5°)
=[2sin50°+2(cos60°cos10°+sin60°sin10°)]/(根号(2)cos5°)
=[2sin50°+2cos50°]/(根号(2)cos5°)
=[2根号(2)cos5°]/(根号(2)cos5°)
=2