发布网友 发布时间:2024-10-01 02:29
共0个回答
解:[a/(a+b)-b/(b-a)-2ab/(a^2-b^2)]/(1/a-1/b)=[a(a-b)+b(a+b)-2ab]/(a^2-b^2)/[(b-a)/(ab)]=[a^2-ab+ab+b^2-2ab]/(a^2-b^2)/[(b-a)/(ab)]=[[a^2+b^2-2ab]/(a^2-b^2)/[(b-a)/(ab)]=[(b-a)^2]/(a+b)(a-b)/[(b-a...
〖a/(a+b)-b/(b-a)-2ab/(a^2-b^2)〗÷(1/a-1/b)=(a^2-ab+ab+b^2-2ab)(a^2-b^2)=(a-b)^2/[(a+b)(a-b)]=(a-b)/(a+b)1/a-1/b=-(a-b)/ab 所以原式=-ab(a-b)/[(a+b)(a-b)]=-ab/(a+b)
...a/a+b-b/b-a-2ab/a^2-b^2)除以(1/a-1/b)其中a+b=3,ab=2 。_百度...先简化(a/a+b-b/b-a-2ab/a^2-b^2)÷(1/a-1/b),代入即可 (a/a+b - b/b-a - 2ab/a^2-b^2)÷(1/a-1/b)=[a*(a-b)+b*(a+b)-2ab)]/[(a+b)(a-b)]*(ab)/(b-a)=(a-b)/(a+b)*(ab)/(b-a)=-ab/(a+b)...
先化简,再求值;[(2a-b/a b)-(b/a-b)]÷{(a-2b/a b) [ab/(a-b)2]}...先化简,再求值;[(2a-b/a+b)-(b/a-b)]÷{(a-2b/a+b)+[ab/(a-b)²]},其中b/a=-1/2 解,得:[(2a-b)(a-b)-b(a+b)]/[(a+b)(a-b)]÷[(a-2b)(a-b)^2+ab(a+b)]/[(a+b)(a-b)^2]==[(2a-b)(a-b)-b(a+b)]/[(a+b)(a-b)]* [...
先化简,再求值:a/(a+b)+b/(a-b)+2ab/(a^2-b^2),其中...a/(a+b)+b/(a-b)+2ab/(a^2-b^2)=[a(a-b)]/(a+b)(a-b)+[b(a+b)]/(a-b)(a+b)+2ab/(a-b)(a+b)=(a^2-ab)/(a+b)(a-b)+(ab+b^2)/(a-b)(a+b)+2ab/(a-b)(a+b)=(a^2-ab+ab+b^2+2ab)/(a+b)(a-b)=(a^2+b^2+2ab)/(a+b)(a...
...求值,a分之a减b除以(a减a分之2ab减b的平方),其中,a等于2016,b等于20...(a-b)/a÷[a-(2ab-b²)/a]=(a-b)/a÷[a²-2ab+b²)/a]=(a-b)/a * a/(a-b)²=1/(a-b)当a=2016,b=2015 原式=1/(2016-2015)=1
先化简,再求值[a/(a的平方-b的平方)-1/(a+b)]÷b/(b-a) 其中a=2,b...- b²) - 1/(a + b)] ÷ b/(b - a)= [a/(a² - b²) -(a - b)/(a² - b²) ] × (b - a)/b = b/(a² - b²) × (b - a)/b = -1/(a + b)把 a = 2,b = -3代入得:原式 = -1/(2 - 3)= 1 ...
先化简,后求值:(a^2 - b^2)/ab -(ab - b^2)/(ab-a^2),其中a=-3/2,b...a/b=-1 (a^2 - b^2)/ab -(ab - b^2)/(ab-a^2)=[(a^2 - b^2)/ab]-[b(a-b)/a(b-a)]=[(a^2 - b^2)/ab]+[b(a-b)/a(a-b)]=[(a^2 - b^2)/ab]+(b/a)=[(a^2 - b^2)/ab]+(b^2/ab)=[(a^2 - b^2)+b^2]/ab =a^2/ab =a/b =-1...
先化简,再求值:a分之a的平方减去b的平方除以(a分之2ab-b的平方-a...解:(a²-b²)/a÷[(2ab-b²)/a-a]=(a+b)(a-b)/a÷(2ab-b²-a²)/a =(a+b)(a-b)/a·[-a/(a-b)²]=-(a+b)/(a-b)∵a=1+√2 b=1-√2 ∴a+b=2 a-b=2√2 ∴原式=-2/2√2=-√2/2 ...
先化简,再求值:(a2-2ab+b2)/(a2-b2)/(1/a-1/b),其中a=根号2+1,b=根号...原式=(a-b)²/(a+b)(a-b)÷(b-a)/ab =(a-b)/(a+b)×[-ab/(a-b)]=-ab/(a+b)=-(2-1)/(2√2)=-√2/4