在复数范围内,方程m³=8的虚数根是
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发布时间：2024-07-21 16:32
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热心网友
时间：2024-07-21 17:36
=8[cos(2nπ)+isin(2nπ)]
m=2[cos(2nπ/3)+isin(2nπ/3)] ; n=0,1,2
n=0, m=2
n=1, m=2[cos(2π/3)+isin(2π/3)]
n=2, m=2[cos(4π/3)+isin(4π/3)]
虚数根= 2[cos(2π/3)+isin(2π/3)] or 2[cos(4π/3)+isin(4π/3)]
