C语言问题 输入一个英文句子 将每个单词的第一个字母改成大写字母...

include <ctype.h> include <string.h> include <stdio.h> int main(int argc, char* argv[]){ char str[100 + 1];int isfirst = 1;char ch;int i = 0;while((ch = getchar()) != EOF){ if(isalpha(ch)){ if(isfirst == 1){ ch = toupper(ch);isfirst = 0;} } else...

if(k==0&&a[i]<97&&a[i]>122)这句有逻辑错误。a[i]不可能同时小于97和大雨122.后面那个&&应该是||。include <ctype.h> char str[100 + 1];int isfirst = 1;char ch;int i = 0;while((ch = getchar()) != EOF)ch = toupper(ch);isfirst = 0;else str[i] = '\0';pri...

程序已在dev-c++下编译确认：/*提取用空格分隔的字符串中的单词，并改单词首字母为大写*/ include<stdio.h> include<stdlib.h> include<ctype.h> int partition(char *s1,char *s2,int pos){ int i,j;i=pos;while(s1[i]==' ')i++;if(s1[i]!='\0'){ j=0;while(s1[i]!='\0...

输入一个字符串:how are You,fine thanks!修改后的字符串:How Are You,Fine Thanks!Press any key to continue

首先判断第一个字母，之后给第一个字母的asc减去32。然后通过printf输出。就可以了

include<ctype.h> include<string.h> include<stdio.h> int main(int argc,char*argv[]){ char str[100+1];int isfirst=1;char ch;int i=0;while((ch=getchar())!=EOF){ if(isalpha(ch)){ if(isfirst==1){ ch=toupper(ch);isfirst=0;} } else { isfirst=1;} str[i++]=...

include <stdio.h>int main(void){ char s[300],*p; printf("Enter a English sentence...\n"); if(fgets(s,300,stdin)){ for(p=s;*p;p++) if(p==s || *(p-1)==' '){ if(*p>='a' && *p<='z') *p&=0xDF; } else if(*p>='A' && *...

include<stdio.h> void main(){ char a[255];char *s=&a[0];scanf("%[^\n]",s);if (*s<='z' && *s>='a') *s-=32;while(*(++s)){ if (*(s-1)==' ' && *s<='z' && *s>='a')s-=32;} s=&a[0];printf("%s",s);} ...

1、在不知道语句第一个单词的首字母是不是大写的情况下，武断地直接将ASCII码值减32 2、i从0开始循环，a[i-1]中的i-1无定义。3、错误与错误1类似，在不知道空格后单词的首字母是不是大写的情况下， 武断地直接将ASCII码值减32

include <conio.h> main(){ char str[100] = {0};printf( "input:\n" );scanf( "%s",str );int i = 0;if( str[0]>='a' && str[0]<='z' ) str[0]=str[0]-'a'+'A';while( str[i] != '\0' ){ if( str[i] == ' ' ){ if( str[i+1]>='a' && str[i...