解方程:x-1分之3-x(x-1)分之x+2=0;x-3分之2-x+3-x分之一=1
发布网友
发布时间：2024-10-02 20:15
共1个回答
热心网友
时间：2024-10-19 13:54
[3x-(x+2)]/[x(x-1)]=0
[2x-2)]/[x(x-1)]=0
2/x=0
无解
(2-x)/(x-3) + 1/(3-x) = 1
(2-x)/(x-3) - 1/(x-3) = 1
(2-x-1)/(x-3) = 1
(1-x)/(x-3) = 1
1-x=x-3
2x=4
x=2
经检验不是增根
∴x=2
热心网友
时间：2024-10-19 13:55
[3x-(x+2)]/[x(x-1)]=0
[2x-2)]/[x(x-1)]=0
2/x=0
无解
(2-x)/(x-3) + 1/(3-x) = 1
(2-x)/(x-3) - 1/(x-3) = 1
(2-x-1)/(x-3) = 1
(1-x)/(x-3) = 1
1-x=x-3
2x=4
x=2
经检验不是增根
∴x=2
