利用89C51串行口设计4位静态数码管显示器，编写汇编程序，要求4位显示器上每隔1S交替地显示“0

发布网友发布时间：2022-05-17 05:03

共2个回答

热心网友时间：2023-10-08 22:43

#include char tt = 0;bit flg;char code table[] = { //共阳段码 0 ~ 9 0xC0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90};void main(){ TMOD = 0x01; TH0 = 0x3C; TL0 = 0xB0; IE = 0x82; TR0 = 1; while (1);}void b() interrupt 1{ TH0 = 0x3C; TL0 = 0xB0; tt++; if (tt == 10) { tt = 0; flg = !flg; if(flg) { SBUF = table[3]; while(!TI); TI = 0; SBUF = table[2]; while(!TI); TI = 0; SBUF = table[1]; while(!TI); TI = 0; SBUF = table[0]; while(!TI); TI = 0; } else { SBUF = table[7]; while(!TI); TI = 0; SBUF = table[6]; while(!TI); TI = 0; SBUF = table[5]; while(!TI); TI = 0; SBUF = table[4]; while(!TI); TI = 0; } }}
仿真截图如下：

热心网友时间：2023-10-08 22:44

4位静态？