如何通过C语言建立一个求二维数组的某一行的最小值以及该最小值对应的列并返回列的函数

发布网友发布时间：2022-05-19 17:09

共1个回答

热心网友时间：2023-10-15 05:28

编写一个程序，对于二维数组 b[2][3]={{1,2,3},{4,5,6}}，验证*(*(b+i)+j)、 *(b[i]+j)、
(*(b+i))[j]与 b[i][j]是相同的。
*/

#include <iostream>
using namespace std;

void main()
{
int b[2][3] = { { 1, 2, 3 }, { 4, 5, 6 } };
for (int i = 0; i < 2; i++)
{
for (int j = 0; j < 3; j++)
{
cout << "经检验：";
//if ((*(*(b + i) + j)) == (*(b[i] + j)) == ((*(b + i))[j]) == (b[i][j]))
{
//cout << "*(*(b+" << i << ")+" << j << ")==*(b[" << i << "] + " << j << ") == (*(b + " << i << "))[" << j << "] == b[" << i << "]["<< j << "]" << endl;
//cout << " b[" << i << "][" << j << "]" << "不成立！" << endl;
if (*(*(b + i) + j) == *(b[i] + j))
{
cout << "*(*(b+" << i << ")+" << j << ")==*(b[" << i << "] + " << j << ")";
}
if (*(b[i] + j) == (*(b + i))[j])
{
cout << "*(b[" << i << "] + " << j << ") == (*(b + " << i << "))[" << j << "]";
}
if ((*(b + i))[j] == b[i][j])
{
cout << " (*(b + " << i << "))[" << j << "] == b[" << i << "][" << j << "]" << endl;
}
}

}
}
system("pause");

}