用JQuery.ajax方法,用post方式传两个int类型的参数给后台tomcat服务器...

发布网友发布时间：2022-04-26 04:55

共1个回答

热心网友时间：2022-04-22 14:59

js代码

var param1 = 12;
var param2 = 24;
$.ajax({
type:"POST",
url:"ajax",
data:{'param1': param1, 'param2': param2},
success:function(data){

}
});

action配置(假如ajax url匹配com.test.Ajax这个类)

<action name="ajax" class="com.test.Ajax">
<result name="success">/success.jsp</result>
</action>

后台代码（Ajax类）

package com.test;

import com.opensymphony.xwork2.ActionSupport;

public class Ajax extends ActionSupport{

private Integer param1;
private Integer param2;
public void setParam1(Integer param1) {
this.param1 = param1;
}
public void setParam2(Integer param2) {
this.param2 = param2;
}

@Override
public String execute() throws Exception {

System.out.println(param1);
System.out.println(param2);
return SUCCESS;
}

}