F.4 quardratic equation
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发布时间：2023-07-15 03:12
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时间：2024-11-25 13:50
2. pqx^2-(p^2+q62)x+pq=0
(1) x^2 + 2mx - n^2 = 0 x = {-(2m) +/- sqrt[(2m)^2 - 4(1)(n^2)]} / 2(1) x = [-2m +/- sqrt(4m^2 - 4n^2)] / 2 x = [-2m +/- 2sqrt(m^2 - n^2)] / 2 x = -m +/- sqrt(m^2 - n^2) (2) ??? 2013-09-17 12:46:30 补充： pqx^2 - (p^2 + q^2)x + pq = 0 x = {-[-(p^2 + q^2)] +/- sqrt{[-(p^2 + q^2)]^2 - 4(pq)(pq)}} / (2pq) x = {(p^2 + q^2) +/- sqrt[(p^2 + q^2)^2 - 4(pq)^2]} / (2pq) x = {(p^2 + q^2) +/- sqrt[(p^2)^2 + 2(pq)^2 + (q^2)^2 - 4(pq)^2]} / (2pq) x = {(p^2 + q^2) +/- sqrt[(p^2)^2 - 2(pq)^2 + (q^2)^2]} / (2pq) 2013-09-17 12:46:36 补充： x = [(p^2 + q^2) +/- sqrt(p^2 - q^2)^2] / (2pq) x = [(p^2 + q^2) +/- (p^2 - q^2)] / (2pq) x = [(p^2 + q^2) + (p^2 - q^2)] / (2pq) or x = [(p^2 + q^2) - (p^2 - q^2)] / (2pq) x = p / q or x = q / p
参考: knowledge
Do you miss the equation for question 2.? 2013-09-17 12:00:32 补充： 50418129 ^_^ 我本想等她加上补充发问然后再答，岂料你那么快速～ 那么把重任交给你吧～ =^o^= 2013-09-17 12:02:38 补充： 第一题也可以考虑用配方法(method of pleting square) x² + 2mx - n² = 0 x² + 2mx = n² x² + 2mx +m² = n² +m² (x+m)² = n² +m² x + m = ±√(n² +m²) x = -m ± √(n² +m²)
