F.4 Quardratic Equations
发布网友
发布时间:2023-07-15 03:12
我来回答
共1个回答
热心网友
时间:2024-11-25 13:54
更新1:Q1. wer: h=18
k=-3
1) k+k-3=-(-3k)/1 2k+3=3k 3=k k=3 3(3-3)=h/1 0=h h=0 2) 3(2x + 3)^2 - 18x = 3(x - 1)^2 + 8 3[(2x)²+2(2x)(3)+3²]-18x=3[x²-2(x)(1)+1²]+8 3(4x²+12x+9)-18x=3(x²-2x+1)+8 12x²+36x+27-18x=3x²-6x+3+8 9x²+24x+16=0 (3x+4)(3x+4)=0 x=-4/3 2013-10-01 12:16:10 补充: Q1用sum of roots & proct of roots 2013-10-01 12:51:51 补充: 打错正负号- - 1) k+k-3=-(-3k)/1 2k-3=3k -3=k k=-3 -3(-3-3)=h/1 -3(-6)=h 18=h h=18 2013-10-01 12:54:31 补充: remember: sum of roots =-b/a proct of roots =c/a