发布网友 发布时间:2023-09-22 14:08
共3个回答
热心网友 时间:2024-12-13 18:40
1.(m^2-4)(m^2-4m+3)/(m+2)(m-3) =(m+2)(m-2)(m-1)(m-3)/(m+2)(m-3) =(m-2)(m-1) 2.已知1/x-1/y=3,求分式2x+3xy-2y/x-2xy-y的值? 分子分母同除xy 原式=(2/y+3-2/x)/(1/y-2-1/x) =(-6+3)/(-5)=3/5热心网友 时间:2024-12-13 18:41
1-(4m-1)\m2-4m+3热心网友 时间:2024-12-13 18:41
1.是[(m2-4)/(m2-4m+3)]÷[(m+2)/(m-3)]吧,它=[(m+2)(m-2)÷(m-1)(m-3)]c×(m-3)/(m+2)=(m-2)/(m-1).