怎么用C语言写个程序找出两个英文句子中相同的英文单词
发布网友
发布时间：2023-08-06 02:53
共3个回答
热心网友
时间：2024-11-30 19:04
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv)
{
char s1[] = "This is test sentence, find all plicated words.";
char s2[] = "Just a test for finding plication words.";
size_t len_s1 =0;
char *s_p = NULL;
char* pch = NULL;
char* psubstr = NULL;
/* make a plication to protect the source */
len_s1 = strlen(s1);
s_p = (char*)malloc(len_s1 * sizeof(char));
if (s_p == NULL)
{
fputs("Memory allocating error", stderr);
}
strncpy(s_p, s1,len_s1);
/* slice the p. string, loop thru 2nd string to compare word by word */
pch = strtok (s_p, " ,."); /* modifying if necessary */
while (pch != NULL)
{
/* printf("%s\n", pch); */ /* debug print */
psubstr = strstr(s2, pch);
if (psubstr != NULL)
printf ("--->%s\n",pch);
pch = strtok (NULL, " ,.");
}
/* release memory allocated by malloc above */
free(s_p);
return 0;
}追问如果不用指针该怎么做
追答① 哪一部分不希望是指针？
② 为什么不希望是指针？ C的特点之一啊？
热心网友
时间：2024-11-30 19:05
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv)
{
char s1[] = "This is test sentence, find all plicated words.";
char s2[] = "Just a test for finding plication words.";
size_t len_s1 =0;
char *s_p = NULL;
char* pch = NULL;
char* psubstr = NULL;
/* make a plication to protect the source */
len_s1 = strlen(s1);
s_p = (char*)malloc(len_s1 * sizeof(char));
if (s_p == NULL)
热心网友
时间：2024-11-30 19:05
可以定义两个字符串，赋值成两个英文句子，
用两个嵌套for循环，一个单词一个单词的比较追问能不能帮我举个程序例子？是不是要用到字符串数组，而且怎么把单词之间的空格符不算进去？
追答声明两个字符串就可以，char a[ ]="i am a student"; char b[ ] = "i am a teacher";
用指针，指向每一个字母，当指针的值是空格的时候，即要指向下一个单词了
char *p=a;
while (*p != ' ')
{
p++;
} 这样可以跳过空格，可以根据你写的程序，决定是用while 或者是 if
