发布网友 发布时间:2022-04-09 07:03
共3个回答
懂视网 时间:2022-04-09 11:24
方法1: 1、创建一个临时表,选取需要的数据。 2、清空原表。 3、临时表数据导入到原表。 4、删除临时表。 mysql> select * from student; +----+------+ | ID | NAME | +----+------+ | 11 | aa | | 12 | aa | | 13 | bb | | 14 | bb | | 15 | bb | | 16 | cc | +----+------+ 6 rows in set mysql> create temporary table temp as select min(id),name from student group by name; Query OK, 3 rows affected Records: 3 Duplicates: 0 Warnings: 0 mysql> truncate table student; Query OK, 0 rows affected mysql> insert into student select * from temp; Query OK, 3 rows affected Records: 3 Duplicates: 0 Warnings: 0 mysql> select * from student; +----+------+ | ID | NAME | +----+------+ | 11 | aa | | 13 | bb | | 16 | cc | +----+------+ 3 rows in set mysql> drop temporary table temp; Query OK, 0 rows affected 这个方法,显然存在效率问题。 方法2:按name分组,把最小的id保存到临时表,删除id不在最小id集合的记录,如下: mysql> create temporary table temp as select min(id) as MINID from student group by name; Query OK, 3 rows affected Records: 3 Duplicates: 0 Warnings: 0 mysql> delete from student where id not in (select minid from temp); Query OK, 3 rows affected mysql> select * from student; +----+------+ | ID | NAME | +----+------+ | 11 | aa | | 13 | bb | | 16 | cc | +----+------+ 3 rows in set 方法3:直接在原表上操作,容易想到的sql语句如下: mysql> delete from student where id not in (select min(id) from student group by name); 执行报错:1093 - You can‘t specify target table ‘student‘ for update in FROM clause 原因是:更新数据时使用了查询,而查询的数据又做了更新的条件,mysql不支持这种方式。 怎么规避这个问题? 再加一层封装,如下: mysql> delete from student where id not in (select minid from (select min(id) as minid from student group by name) b); Query OK, 3 rows affected mysql> select * from student; +----+------+ | ID | NAME | +----+------+ | 11 | aa | | 13 | bb | | 16 | cc | +----+------+ 3 rows in set http://www.cnblogs.com/nzbbody/p/4470638.htmlmysql删除重复记录,保存Id最小的一条
标签:
热心网友 时间:2022-04-09 08:32
你的字段都没搞出来,怎么啊,我假如你只有三个字段,一个ID,一个column1,column2吧:热心网友 时间:2022-04-09 09:50
你的字段都没搞出来,怎么啊,我假如你只有三个字段,一个ID,一个column1,column2吧: