oracle取前几条记录

发布网友发布时间：2022-04-09 03:38

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热心网友时间：2022-04-09 05:08

比如想取出100-150条记录,按照tname排序 select tname,tabtype from (select tname,tabtype,row_number() over ( order by tname ) rn from tab)where rn between 100 and 150; 2. 使用rownum 虚列 select tname,tabtype from (select tname,tabtype,rownum rn from tab where rownum <= 150)where rn >= 100; 注释：使用序列时不能基于整个记录集合来进行排序,假如指定了order by子句,排序的的是选出来的记录集的排序。在ORACLE如果想取一张表按时间排序后的前5条最新记录: 方法一\二对,方法三错 SELECT GUID,title,content FROM (SELECT GUID,title,content, row_number() over (order by releasetime desc)tm FROM web_LO_Article WHERE funID=20 and content like '%<img %') WHERE tm between 1 and 5 或者:select * from (select * from web_LO_Article where funID=20 and content like '%<img %' order by releasetime desc)where rownum<6 ROW_NUMBER() 就是生成一个顺序的行号,而他生成顺序的标准,就是后面紧跟的OVER(ORDER BY ReportID) SELECT GUID,title,content,releaseTimeFROM web_LO_Article WHERE funID=20 and rownum<6 and content like '%<img %' order by releaseTime desc 方法三表示:查询数据库中的前5条数据，然后在对它们按时间降序排列。 select * from (select row_number() over(order by id) rn from et_sys_treebase) where rn between 3 and 5表的记录就可以查询出来，结果是从3到5的记录 //河南省，点击率数最高的前8个地市