PHP接收URL中的参数的问题

发布网友发布时间：2022-04-30 11:01

共3个回答

热心网友时间：2022-06-21 12:29

在JS端，针对这个+号和&号写一个自己用的编码函数，因为普通escape等编码已经满足不了你的需要了。
给你一个例子，著名的BASE64编码

var BASE64={

enKey: 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/',

deKey: new Array(
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63,
52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1,
-1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,
15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1,
-1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1
),

encode: function(src){

var str=new Array();
var ch1, ch2, ch3;
var pos=0;

while(pos+3<=src.length){
ch1=src.charCodeAt(pos++);
ch2=src.charCodeAt(pos++);
ch3=src.charCodeAt(pos++);
str.push(this.enKey.charAt(ch1>>2), this.enKey.charAt(((ch1<<4)+(ch2>>4))&0x3f));
str.push(this.enKey.charAt(((ch2<<2)+(ch3>>6))&0x3f), this.enKey.charAt(ch3&0x3f));
}

if(pos<src.length){
ch1=src.charCodeAt(pos++);
str.push(this.enKey.charAt(ch1>>2));
if(pos<src.length){
ch2=src.charCodeAt(pos);
str.push(this.enKey.charAt(((ch1<<4)+(ch2>>4))&0x3f));
str.push(this.enKey.charAt(ch2<<2&0x3f), '=');
}else{
str.push(this.enKey.charAt(ch1<<4&0x3f), '==');
}
}

return str.join('');
},

decode: function(src){

var str=new Array();
var ch1, ch2, ch3, ch4;
var pos=0;

src=src.replace(/[^A-Za-z0-9\+\/]/g, '');
//decode the source string in partition of per four characters.
while(pos+4<=src.length){
ch1=this.deKey[src.charCodeAt(pos++)];
ch2=this.deKey[src.charCodeAt(pos++)];
ch3=this.deKey[src.charCodeAt(pos++)];
ch4=this.deKey[src.charCodeAt(pos++)];
str.push(String.fromCharCode(
(ch1<<2&0xff)+(ch2>>4), (ch2<<4&0xff)+(ch3>>2), (ch3<<6&0xff)+ch4));
}

if(pos+1<src.length){
ch1=this.deKey[src.charCodeAt(pos++)];
ch2=this.deKey[src.charCodeAt(pos++)];
if(pos<src.length){
ch3=this.deKey[src.charCodeAt(pos)];
str.push(String.fromCharCode((ch1<<2&0xff)+(ch2>>4), (ch2<<4&0xff)+(ch3>>2)));
}else{
str.push(String.fromCharCode((ch1<<2&0xff)+(ch2>>4)));
}
}

return str.join('');
}
};

使用方法都不需要创建实例，直接使用base64的对象方法则可。

base64.encode(string xxx);//编码
string xxx=base64.decode(base64.encode(string xxx));//解码

热心网友时间：2022-06-21 12:29

<a href="a.php?x=<?=urlencode('abc%2Bdefgh&123456') ?>">click</a>
<?
echo $_GET['x'];
?>
你这样写就可以获取到x的真正的值了

热心网友时间：2022-06-21 12:30

首先 &是网址里的变量分割符合如果不是必须强烈不推荐
a.php?x=abc%2Bdefgh&d=123456
这样就获取两个参数
$_GET['x'] 和$_GET['d];
你这样一搞就全乱了
如果非要这样的话，我试着帮你写个
<?
$str= $_SERVER['QUERY_STRING'];
$str=split('=',$str)
$x=urldecode($str[1]);
echo $x;
?>