c语言,如何用指针向函数传递一个三维数组,并在函数内用该指针改变三位数...

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include <stdio.h>#include <stdlib.h>int main(){ //有效部分int ***p = (int***)malloc(sizeof(int**)*3);for (int i = 0; i < 3; ++i){p[i] = (int**)malloc(sizeof(int*) * 4);}for (int i = 0; i < 3; ++i){for (int j = 0; j < 4; ++j){p...

int i,j,k;char ***m = (char***)malloc(H* sizeof(char**)); //定义动态三维数组m for(j=0; j<m; j++){ m[j] = (char**)malloc(6*sizeof(char*));for(k=0; k<n; k++){ m[j][k] = (char*)malloc(32*sizeof(char));} } char *n;n=(char *)malloc...

include<iostream>using namespace std;#define N 3//修改1void Visual(char (*a)[N][N], int n)//修改3，以“修改2”的形式定义数组才好定义形参 {int i, j;for (i = 0; i < N; i++){for (j = 0; j < N; j++){cout << a[n][i][j] << " ";//修改4 }cout <...

数组名就是指针，例如：include <stdio.h> void pr(char *p){ printf(p);} void main(void){ char s[] = "abc";pr(s);}

struct Point{ int x;int y;};Point* P1 = (Point*)malloc(你需要的数目*sizeof(Point));完全不需要3维数组, 一个结构加个指针就可以了.

由于题目没有说明数组是方阵，所以本答案按一般二维数组处理。代码文本：include "stdio.h"define N 3 define M 5 void myf(int a[][M],int b[][N],int i,int j){//本函数将数组a转置为b int t;for(t=j-1,i--;i>=0;i--)for(j=t;j>=0;b[j][i]=a[i][j--]);} int...

include <stdio.h> long cube(int x){return x*x*x;}int main(){int x,y;scanf("%d%d",&x,&y);printf("%d^3 + %d^3 = %ld",x,y,cube(x) + cube(y));printf("%d^3 - %d^3 = %ld",x,y,cube(x) - cube(y));return 0;} ...

int main(void){ int *a, *b;int num1[N], num2[N];for (a = num1; a < num1 + N; a++)scanf ("%d", a);for (b = num2; b < num2 + N; b++)scanf ("%d", b);a = num1;//重新指向首地址 b = num2;//重新指向首地址 Swap (a, b, N);printf ("***...

会的，因为多个指针可以指向一个地址，形参改变地址中的内容，实参也会改变，因为调用时你将形参的地址指向实参了。