发布网友 发布时间:2024-05-01 14:24
共1个回答
热心网友 时间:2024-08-21 15:43
syms I x1 x2; x1 =
-1/500*log(2500*I^(3/2)*10^(1/2))
-1/500*log(2500*I^(3/2)*10^(1/2))
-1/500*log(-2500*I^(3/2)*10^(1/2))
-1/500*log(-2500*I^(3/2)*10^(1/2))
x2 =
1/500*2^(1/2)*log(1/50*10^(1/2)/I^(1/2))^(1/2)
-1/500*2^(1/2)*log(1/50*10^(1/2)/I^(1/2))^(1/2)
1/500*2^(1/2)*log(-1/50*10^(1/2)/I^(1/2))^(1/2)
-1/500*2^(1/2)*log(-1/50*10^(1/2)/I^(1/2))^(1/2)