如何卡诺图化简逻辑式
发布网友
发布时间：2024-04-16 19:58
共1个回答
热心网友
时间：2024-04-18 07:00
F=A'(C⊕D)+BC'D+ACD'+AB'C'D
F=A'(C⊕D)+C'D(B+AB')+ACD'
F=A'(C⊕D)+(A+B)C'D+ACD'
F=A'(C⊕D)+A(C⊕D)+BC'D
F=(A+A')(C⊕D)+BC'D
F=C'D+CD'+BC'D
F=C'D(1+B)+CD'=C'D+CD'
F= C⊕D
