计算a/(a-b)(a-c)+b/(b-c)(b-a)+c/(c-a)(c-b)详细讲解
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发布时间:2024-04-10 02:15
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时间:2024-04-11 22:07
a/(a-b)(a-c)+b/(b-c)(b-a)+c/(c-a)(c-b)
=a/(a-b)(a-c)-b/(b-c)(a-b)+c/(a-c)(b-c)
=a(b-c)/(a-b)(a-c)(b-c)-b(a-c)/(a-b)(b-c)(a-c)+c(a-b)/(a-b)(a-c)(b-c)
=[a(b-c)-b(a-c)+c(a-b)]/(a-b)(a-c)(b-c)
=(ab-ac-ab+bc+ac-bc)/(a-b)(a-c)(b-c)
=0/(a-b)(a-c)(b-c)
=0