观察下列各式:1/6=1/2.3=1/2-1/3;1/12=1/3.4=1/3-1/4;1/20=1/4.5=1...

发布网友发布时间：2024-01-18 01:44

共4个回答

热心网友时间：2024-07-22 23:10

热心网友时间：2024-07-22 23:06

解:
1/（x-3)- 1/（x-2)- 1/(x-1)(x-3)+ 1/(x-2)- 1/(x-1)=-1

1/（x-3)- 1/(x-1)(x-3)- 1/(x-1)=-1

2/(x-1)（x-3)- 1/(x-1)(x-3)=-1

1/(x-1)(x-3)=-1

(x-1)(x-3)=-1

x^2-4x+3=-1
x^2-4x+4=0
(x-2)^2=0
x=2
回答者：凉夏樱一 - 见习魔法师三级 6-9 13:34
1/（x-3)- 1/（x-2)- 1/(x-1)(x-3)+ 1/(x-2)- 1/(x-1)=-1

1/（x-3)- 1/(x-1)(x-3)- 1/(x-1)=-1

2/(x-1)（x-3)- 1/(x-1)(x-3)=-1

1/(x-1)(x-3)=-1

(x-1)(x-3)=-1

x^2-4x+3=-1
x^2-4x+4=0
(x-2)^2=0
x=2

热心网友时间：2024-07-22 23:04

1/（x-3)- 1/（x-2)- 1/(x-1)(x-3)+ 1/(x-2)- 1/(x-1)=-1

1/（x-3)- 1/(x-1)(x-3)- 1/(x-1)=-1

2/(x-1)（x-3)- 1/(x-1)(x-3)=-1

1/(x-1)(x-3)=-1

(x-1)(x-3)=-1

x^2-4x+3=-1
x^2-4x+4=0
(x-2)^2=0
x=2