shell脚本(linux)

发布网友发布时间：2022-04-24 01:32

共2个回答

热心网友时间：2023-10-18 19:32

if cat /etc/passwd | cut -d":" -f1 | grep -E "\busr2\b" > /dev/null 2>&1
then
echo "Account usr2 exists!"
else
useradd usr2 -d /home/usr2 -s /sbin/nologin && edquota -p usr1 usr2
fi

exit 0

----------------------

直接grep ^usr2不能精确匹配，类似usr22这样的也能被匹配到，可能造成错误

热心网友时间：2023-10-18 19:33

MARK=`cat /etc/passwd | grep ^usr2`
if [ -z $MARK ] ; then
useradd usr2 -s /sbin/nologin
edquota -p usr1 usr2
else
echo "user usr2 exists"
fi

exit 0

热心网友时间：2023-10-18 19:32

热心网友时间：2023-10-18 19:33

MARK=`cat /etc/passwd | grep ^usr2`
if [ -z $MARK ] ; then
useradd usr2 -s /sbin/nologin
edquota -p usr1 usr2
else
echo "user usr2 exists"
fi

exit 0