求C语言程序大神!

发布网友发布时间：2023-05-10 02:46

共2个回答

热心网友时间：2023-06-21 20:06

#include <stdio.h>
#define N 1000 //预定义员工个数

/*定义员工结构体*/
struct Employee
{
   char ID[20];
   char Name[20];
   float Mark1;
};

/*声明员工数组及员工数量*/
struct Employee Employees[N];
int num=0;

/*插入员工信息*/
int Employee_Insert(){
     while(1){
         printf("请输入员工ID:");
         scanf("%s",&Employees[num].ID);
         getchar();
         printf("请输入姓名:");
         scanf("%s",&Employees[num].Name);
         getchar();
         printf("请输入业绩:");
         scanf("%f",&Employees[num].Mark1);
         getchar();
         num++;
         printf("是否继续?(y/n)");
         if (getchar()=='n'){
              break;
         }
     }
   return num;
}
/*按业绩排序*/
void Employee_Sort(){
  int i,j;
  struct Employee tmp;
  for (i=0;i<num;i++){
      for (j=1;j<num-i;j++){
          if (Employees[j-1].Mark1<Employees[j].Mark1){ //降序
                tmp=Employees[j-1];
                Employees[j-1]=Employees[j];
                Employees[j]=tmp;
          }
      }
  }
}
/*显示员工信息*/
void Employee_Display()  {
     int i,t;
     printf("%10s%10s%20s\n","工号","姓名","业绩"); //显示格式可自行调整
     printf("---------------------------------------------------------\n");
     if(num>10)//员工不超过10人，全部显示
      //超过10人，显示排序前10
        t=10;
     else
        t=num;
     for(i=0;i<t;++i){  //显示格式可自行调整
        printf("%10s%10s%18.2f\n",
        Employees[i].ID,Employees[i].Name,Employees[i].Mark1);
     }
}
/*主程序*/
int  main(){
   Employee_Insert();  //输入员工信息
   Employee_Sort();  //排序
   Employee_Display();
   return 0;
}

热心网友时间：2023-06-21 20:06

#include "stdio.h"

#include "string.h"

#include "math.h"

int main()

{

char a[20]={0};

int i,len;

int out=1;

printf("please input a integer str:");

gets(a);

len=strlen(a);

for(i=0;i<len;i++)

out+=(a[i]-'0')*pow(10.0,len-1-i);

printf("该整数字符串转成整数再加上1后值为%d\n",out);

}

结果：

#include "stdio.h"

#include "string.h"

#include "math.h"

int main()

{

char a[50]={0};

char number[50]={0};

int i,len,k=0;

int out=1;

printf("please input a str:");

gets(a);

len=strlen(a);

for(i=0;i<len;i++)

if(a[i]>='0' && a[i]<='9')

number[k++]=a[i];

for(i=0;i<k;i++)

out+=(number[i]-'0')*pow(10.0,k-1-i);

printf("该字符串中的整数字符串转成整数再加上1后值为%d\n",out);

}

结果：