高二数学数列的应用题,3道,要求详细过程!!
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发布时间:2022-10-30 15:18
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热心网友
时间:2023-10-12 00:16
1、平均造价亦即(500+600+~~~+(400+100n))/n<=950==》》n<=10
2、列式:(~~~(((45*0.92+x)*0.92+x)*0.92+x)~~~)*0.92+x<=80
===>> 45*0.92^n+(0.92^n+0.92^(n-1)+~~~+0.92+1)*x<=80
===>> 化简(等比数列求和)(2.5*x-9)*(1-0.92^n)<=7
左式MAX=2.5*x-9 =====》》》2.5*x-9<=7 ====》》》 x<=6.4
3、(1)128*1.5^(2017-2011)=1458
(2) 128+128*1.5+128*1.5^2+~~~+128*1.5^n>=10000
====>>> n>=8.1~~~~n=9~~~~~2020年追问其实在提问之后我就做好了啊,不过你让我发现了最后一题我的错误,谢谢咯~~
热心网友
时间:2023-10-12 00:16
1、平均造价亦即(500+600+~~~+(400+100n))/n<=950==》》n<=10
2、列式:(~~~(((45*0.92+x)*0.92+x)*0.92+x)~~~)*0.92+x<=80
===>> 45*0.92^n+(0.92^n+0.92^(n-1)+~~~+0.92+1)*x<=80
===>> 化简(等比数列求和)(2.5*x-9)*(1-0.92^n)<=7
左式MAX=2.5*x-9 =====》》》2.5*x-9<=7 ====》》》 x<=6.4
3、(1)128*1.5^(2017-2011)=1458
(2) 128+128*1.5+128*1.5^2+~~~+128*1.5^n>=10000
====>>> n>=8.1~~~~n=9~~~~~2020年追问其实在提问之后我就做好了啊,不过你让我发现了最后一题我的错误,谢谢咯~~