小明送外卖 C语言

发布网友发布时间：2022-11-11 03:57

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热心网友时间：2024-12-03 04:30

当外卖赚钱那么好赚的啊！！！！！

思路：

各自份数：k(开封菜)c（麦当劳）p(必胜客)

收入: money 总份数:total

k * 20 + c * 12 + p * 8 = money

k + c + p = total -> p = total - c - k

->k*20 + c * 12 + p * 8 = money & p 不能小于0

开始编程：

int main()
{
int k,c,p;
int total,money;
printf("外卖人数:");
scanf("%d", &total);
printf("总收入:");
scanf("%d", &money);

bool found = false;
for (k = 0; k <= total; k ++)
{
for (c = 0; c <= total; c ++)
{
p = total - k - c;
if (p < 0)
{
continue;
}
else
{
int tmp = k * 20 + c * 12 + p * 8;
if (tmp == money)
{
found = true;
printf("KFC = %d MC = %d PIZZ = %d \n", k, c, p);
}
}
}
}

if (!found)
{
printf("No Solution \n");
}
return 0;
}

热心网友时间：2024-12-03 04:31

#include<stdio.h>
int main()
{
int n,m,i,j,k,flag=1;
scanf("%d%d",&n,&m);
for(i=0;i<=n;i++)
for(j=0;j<=n-i;j++)
for(k=0;k<=n-i-j;k++)
{
if(i*20+j*12+k*8==m)
{
printf("%d %d %d\n",i,j,k);//输出多组，没有排序
flag=0;
}
}
if(flag)printf("No Solution!\n");
return 0;
}