fmincon函数的使用
发布网友
发布时间：2022-07-13 04:21
共2个回答
热心网友
时间：2023-10-23 18:51
>> [x,fval]=fmincon('fmin',x0,[],[],[],[],-1.68,1.68)
Optimization terminated: magnitude of directional derivative in search
direction less than 2*options.TolFun and maximum constraint violation
is less than options.TolCon.
No active inequalities.
x =
1.668593592364594 0.581614920319626
fval =
-27.187778596177679
结果正确着呢！
因为你这是非线性有约束的最优化问题，只能用这个函数了
热心网友
时间：2023-10-23 18:51
