VB 读取行数问题
发布网友
发布时间：2023-04-05 17:34
共2个回答
热心网友
时间：2024-04-10 22:59
TextBox 是以 vbCr+vbLf 为分行符号， 如果我们要逐一读取 TextBox 每一行， 无非是寻找 vbCr+vbLf 的所在位置， 然后取出每一行的字串， 不过这个方法不快，而且如果我们要读取第 N 行数据，还是要从第 1、2、…N-1 行逐一读起，实在麻烦。 还好 Windows API 提供有读取 TextBox 第 N 行的功能， 细节如下：
1、API 的声明：
Public Const EM_GETLINE = &HC4
Public Const EM_LINELENGTH = &HC1
Public Const EM_LINEINDEX = &HBB
Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Declare Sub RtlMoveMemory Lib "KERNEL32" (lpvDest As Any, lpvSource As Any, ByVal cbCopy As Long)
2. 程序范例：
Sub TB_GetLine(ByVal hWnd As Long, ByVal whichLine As Long, Line As String)
Dim length As Long, bArr() As Byte, bArr2() As Byte, lc As Long
lc = SendMessage(hWnd, EM_LINEINDEX, whichLine, ByVal 0&)
length = SendMessage(hWnd, EM_LINELENGTH, lc, ByVal 0&)
If length > 0 Then
ReDim bArr(length + 1) As Byte,bArr2(length - 1) As Byte
Call RtlMoveMemory(bArr(0), length, 2) '准备一个存储器，传递消息之前先在存储器的前两个字节填入存储器的长度
Call SendMessage(hWnd, EM_GETLINE,whichLine, bArr(0))
Call RtlMoveMemory(bArr2(0), bArr(0), length)
Line = StrConv(bArr2, vbUnicode)
Else
Line = ""
End If
'教程中国.百万教程
End Sub
' 假设要读取 Text1 第 5 行的数据
Dim S As String
Call TB_GetLine( Text1.hWnd, 5, S )
' 传回值 S 即等于第 5 行的数据
（ 注：TextBox 的行次是从 0 起算。）
热心网友
时间：2024-04-10 22:59
