威布尔分布两个参数的求法

发布网友 发布时间：2022-04-29 08:20

我来回答

共1个回答

热心网友 时间：2023-11-04 13:15

matlab威布尔布两参数
wblfit

Weibull parameter estimates
Syntax

parmhat = wblfit(data)
[parmhat,parmci] = wblfit(data)
parmhat,parmci] = wblfit(data,alpha)
[...] = wblfit(data,alpha,censoring)
[...] = wblfit(data,alpha,censoring,freq)
[...] = wblfit(...,options)
==========================
data = wblrnd(0.5,0.8,100,1);
[parmhat, parmci] = wblfit(data)
parmhat =
0.5861 0.8567
parmci =
0.4606 0.7360
0.7459 0.9973追问您能看下我的追问吗？我看不太懂您发的程序

热心网友 时间：2023-10-13 12:17

matlab威布尔布两参数
wblfit

Weibull parameter estimates
Syntax

parmhat = wblfit(data)
[parmhat,parmci] = wblfit(data)
parmhat,parmci] = wblfit(data,alpha)
[...] = wblfit(data,alpha,censoring)
[...] = wblfit(data,alpha,censoring,freq)
[...] = wblfit(...,options)
==========================
data = wblrnd(0.5,0.8,100,1);
[parmhat, parmci] = wblfit(data)
parmhat =
0.5861 0.8567
parmci =
0.4606 0.7360
0.7459 0.9973追问您能看下我的追问吗？我看不太懂您发的程序

热心网友 时间：2023-10-13 12:17

matlab威布尔布两参数
wblfit

Weibull parameter estimates
Syntax

parmhat = wblfit(data)
[parmhat,parmci] = wblfit(data)
parmhat,parmci] = wblfit(data,alpha)
[...] = wblfit(data,alpha,censoring)
[...] = wblfit(data,alpha,censoring,freq)
[...] = wblfit(...,options)
==========================
data = wblrnd(0.5,0.8,100,1);
[parmhat, parmci] = wblfit(data)
parmhat =
0.5861 0.8567
parmci =
0.4606 0.7360
0.7459 0.9973追问您能看下我的追问吗？我看不太懂您发的程序