PHP实现：如何在只给定单链表中某个结点的指针的情况下删除该结点

发布网友 发布时间：2022-04-06 06:48

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懂视网 时间：2022-04-06 11:10

php实现链表的方法：

首先定义一个节点类

class Node{
 public $val;
 public $next;
 function __construct($val=null){
 $this->val = $val;
 $this->next = null;
 }
}

链表的实现类

class MyLinkedList {
 public $dummyhead; //定义一个虚拟的头结点
 public $size;
 
 function __construct() {
 $this->dummyhead = new Node(); 
 $this->size = 0;
 }
 
 
 function get($index) {
 if($index < 0 || $index >= $this->size)
  return -1;
 $cur = $this->dummyhead;
 for($i = 0; $i < $index; $i++){
  $cur = $cur->next;
 }
 return $cur->next->val;
 }
 
 function addAtHead($val) {
 $this->addAtIndex(0,$val);
 }
 
 
 function addAtTail($val) {
 $this->addAtIndex($this->size,$val);
 }
 
 function addAtIndex($index, $val) {
 if($index < 0 || $index > $this->size)
  return;
 $cur = $this->dummyhead;
 for($i = 0; $i < $index; $i++){
  $cur = $cur->next;
 }
 $node = new Node($val);
 $node->next = $cur->next;
 $cur->next = $node;
 $this->size++;
 }
 
 function deleteAtIndex($index) {
 if($index < 0 || $index >= $this->size)
  return;
 $cur = $this->dummyhead;
 for($i = 0; $i < $index; $i++){
  $cur = $cur->next;
 }
 $cur->next = $cur->next->next;
 $this->size--;
 }
}

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热心网友 时间：2022-04-06 08:18