关于sqlite3查询函数get_table的第三个参数的问题
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发布时间：2022-04-21 20:26
共3个回答
懂视网
时间：2022-04-08 00:20
http://stackoverflow.com/questions/1274432/sqlite-parameters-not-allowing-tablename-as-parameter
Generally one cannot use SQL parameters/placeholders for database identifiers (tables, columns, views, schemas, etc.) or database functions (e.g., CURRENT_DATE), but instead only for binding literal values.
placeholder 占位符
identifiers 标识符，认同者；检验人，鉴定人
literal 文字的；逐字的；无夸张的
With server-side support for parameterized (a.k.a. prepared) statements, the DB engine parses your query once, remembering out the peculiars of any parameters -- their types, max lengths, precisions, etc. -- that you will bind in subsequent executions of the already-parsed query. But the query cannot be properly parsed into its syntactic elements if critical bits, like database objects, are unknown.
peculiar 特权；特有财产
precisions 精度，[数] 精密度；精确
subsequent 后来的，随后的
syntactic 句法的；语法的；依据造句法的
critical 鉴定的；[核] 临界的；批评的，爱挑剔的；危险的；决定性的；评论的
So, one generally has to substitute table names oneself, in a stored procedure or in client code which dynamically concats/interpolates/whatevers the SQL statement to be properly executed. In any case, please remember to use your SQL API‘s function for quoting database identifiers, since the API won‘t do it for you.
substitute 代用品；代替者
stored procedur 存储过程
concat 合并多个数组；合并多个字符串
interpolate vt. 篡改；插入新语句 vi. 插入；篡改
quote n. 引用 vi. 报价；引用；引证 vt. 报价；引述；举证
SQLiteParameter不能将TableName作为参数
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热心网友
时间：2022-04-07 21:28
name | id
-----------------------
The Junior Mint | 43
The Smelly Car | 28
The Fusilli Jerry | 21
那么result数组的格式如下
result [0] = "name";
result [1] = "id";
result [2] = "The Junior Mint";
result [3] = "43";
result [4] = "The Smelly Car";
result [5] = "28";
result [6] = "The Fusilli Jerry";
result [7] = "21";
你可以根据这个判断你的是否可行
参考：http://www.phei.com.cn/mole/goods/wssd_content.jsp?bookid=30648
热心网友
时间：2022-04-07 22:46
