在div+css中,如何实现图片跟随鼠标任意移动
发布网友
发布时间：2022-04-20 20:43
共2个回答
热心网友
时间：2022-04-20 22:12
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>鼠标的距离</title>
<script type="text/javascript">
var mouseX;
var mouseY;
function show(event) {
var infoDiv = document.getElementById('infoDiv');
mouseOver(event);
document.getElementById("a").innerHTML = mouseX+" "+mouseY ;
infoDiv.style.display = "block";
infoDiv.innerHTML = mouseX+" "+mouseY;
infoDiv.style.left = mouseX + 10 + "px";
infoDiv.style.top = mouseY + 10 + "px";
}
function hide() {
var infoDiv = document.getElementById('infoDiv').style.display = "none";;
}
function mouseOver(obj) {
e = obj || window.event;
// 此处记录鼠标停留在组建上的时候的位置, 可以自己通过加减常量来控制离鼠标的距离.
mouseX = e.layerX|| e.offsetX;
mouseY = e.layerY|| e.offsetY;
}
</script>
</head>
<body>
<div onmousemove="show(event);" onmouseout="hide();" style="margin:150px ; background:#ff0; height:300px; width:300px; position:relative; ">鼠标相对于触发事件元素的位置<strong id="a"></strong>
<div id="infoDiv" style="display: none; position: absolute; width: 100px; height: 100px; background-color: #F1F19B;"></div>
</div>
</body>
</html>
兼容火狐哦
热心网友
时间：2022-04-20 23:30
